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NEW QUESTION: 1
Which two protocols enable Cisco Configuration Professional to pull IPS alerts from a Cisco ISR router? (Choose two.)
A. SDEE
B. TFTP
C. syslog
D. FTP
E. HTTPS
F. SSH
Answer: A,E
Explanation:
http://www.cisco.com/en/US/prod/collateral/iosswrel/ps6537/ps6586/ps6634/prod_white_paper0900aecd805c4ea8.html
Step 4: Enabling IOS IPS
The fourth step is to configure IOS IPS using the following sequence of steps:
Step 4.1: Create a rule name (This will be used on an interface to enable IPS)
ip ips name <rule name>< optional ACL>
router#configure terminal router(config)# ip ips name iosips
You can specify an optional extended or standard access control list (ACL) to filter the traffic that will be scanned by this rule name. All traffic that is permitted by the ACL is subject to inspection by the IPS. Traffic that is denied by the ACL is not inspected by the IPS.
router(config)#ip ips name ips list ?
<1-199> Numbered access list
WORD Named access list
Step 4.2: Configure IPS signature storage location, this is the directory `ips' created in Step 2
ip ips config location flash:<directory name>
router(config)#ip ips config location flash:ips
Step 4.3: Enable IPS SDEE event notification
ip ips notify sdee router(config)#ip ips notify sdee
To use SDEE, the HTTP server must be enabled (via the `ip http server' command). If the HTTP server is not enabled, the router cannot respond to the SDEE clients because it cannot see the requests. SDEE notification is disabled by default and must be explicitly enabled.

NEW QUESTION: 2
Drag and Drop Question
Drag and drop the IPv4 network subnets from the left onto the correct usable host ranges on the right Select and Place:

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet
172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111 1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is 172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or 172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet. Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 3
You need to design the street team mobile application for creating sales orders in the mobile application.
Which technologies should you use? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation: