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NEW QUESTION: 1
Examine the following set of RMAN commands:
RKAN> CONFIGURE CHANNEL del DEVICE TYPE DISK FORMAT ' /u02/backup/%U' ; RKAN> RUN
{
ALLOCATE CHANNEL chl DEVICE TYPE DISK;
EXECUTE SCRIPT arc_backup;
}
Which statement is true about the RMAN run block execution?
A. The new channel, chi, is ignored because a channel has been configured already.
B. The execution of the script fails because multiple channels cannot exist simultaneously.
C. The persistent configuration parameter,DC1, is overridden because a new channel is allocated in the RMAN run block.
D. The script is executed and bothDC1and chi channels are used for script execution.
Answer: C

NEW QUESTION: 2
Which AEM feature would allow you to work on a future version of your site while still altering the current
version? (Choose the best answer.)
A. Launches
B. Rollout configurations
C. Branching
D. Versioning
Answer: A

NEW QUESTION: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.0.0.0.1
B. Permit 10.0.0.1.0.0.0.0
C. Permit 10.0.0.1.0.0.0.254
D. Permit 10.0.0.0.255.255.255.254
Answer: C
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 4
Which three actions are required when configuring NAT-PAT? (Choose three)
A. Specify an 1Pv4-to-1Pv6 translation.
B. Specify an 1Pv6-to-1Pv4 translation.
C. Specify a: :/96 prefix that will map to an IP4 address.
D. Enable NAT-PT globally.
E. Specify a ::/32 prefix that will map to an 1Pv6 address.
F. Specify a: :/48 prefix that will map to a MAC address.
Answer: A,B,C