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NEW QUESTION: 1
UC would like to capture qualification information for new leads (e.g. whether or not a person is a decision
maker). The information should also appear in the contact record once the lead has been converted. Which
approach should a consultant recommended?
A. Create a custom field on lead and contact object, advice user to select it for transfer during conversion.
B. Create a custom field on lead and contact object, configure mapping for these two fields for conversion.
C. Create a custom field on lead and contact object; these fields will be mapped automatically during
conversion.
D. Create a custom field on lead and contact object, utilize a trigger to transfer the value after conversion.
Answer: B

NEW QUESTION: 2
Delroy McWilliams, a quantitative analyst with Churn Brothers Brokerage, is examining a data sample and has amassed the following information:
Standard deviation of the sample: 70
Number of observations: 600
Sample mean: 812
Assume that Mr. McWilliams formulates a null hypothesis that states that the value of the population mean is equal to 800. Additionally, assume that the population standard deviation is unknown. Given this information, what is the standard error of the estimate? Further, what is the test statistic? Choose the best answer.
A. 8.370; 1.434
B. 2.858; 11.60
C. 0.014; 11.834
D. 0.014; 857.143
E. 8.370; 4.148
F. None of these answers is completely correct.
G. 2.858; 1.40
Answer: F
Explanation:
Explanation/Reference:
Explanation:
The standard error and test statistic for this example is 2.858 and 4.199, respectively. Therefore, none of these answers is correct.
If the population standard deviation is unknown, as in this example, the standard error of the estimate is found by using the following equation:
{Standard error = s / square root of n} where s = the sample standard deviation and n = the number of observations in the sample.
In this example, all of the necessary information has been provided, and the determination of the standard error of the estimate is found as:
{Standard error = [70 / 24.495] = 2.858}
Now that the standard error of the estimate has been calculated, the test statistic can be found by using the following equation:
{Test statistic = [sample statistic - value of the population parameter under the null hypothesis] / standard error of the sample statistic].
Again, all of the necessary information has been provided, and the calculation of the test statistic is found as follows:
{Test statistic = [812 - 800] / 2.858 = 4.199}

NEW QUESTION: 3
Refer to the exhibit.
Which statement about the information that is displayed within the Cisco Spectrum Expert tool is true?

A. Channel 6 cannot be used for Wi-Fi.
B. Non-Wi-Fi interference on channel 1 would cause major performance issues for APs on that channel.
C. The AP on channel 11 is at maximum throughput capacity.
D. Bluetooth interference can be the cause of client connection issues.
Answer: B

NEW QUESTION: 4
There are different classes of mutual funds. Classes that typically do not have a front-end sales load.
Instead they may impose a contingent deferred sales load and a 12b-1 fee (along with other annual expenses) is called:
A. Class B
B. Class A
C. Both B&C
D. Class C
Answer: A