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NEW QUESTION: 1
You must migrate product data from a third-party database into Dynamics 365 Finance. The data includes units of measure and accounting currency.
You need to identify the data entity types.
What should use? To answer, drag the appropriate entity types to the correct data. Each entity type may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Reference:
https://docs.microsoft.com/en-us/dynamics365/fin-ops-core/dev-itpro/data-entities/data-entities

NEW QUESTION: 2
組織は、区分化のために単一のアプリケーションの複数のコンポーネントを作成しました。現在、すべてのコンポーネントは単一のEC2インスタンスでホストされています。セキュリティ上の理由により、組織はすでにVPCを使用しているにもかかわらず、個別のモジュールに2つの個別のSSLを実装したいと考えています。組織はどのようにして単一のインスタンスでこれを達成できますか？
A. それぞれ異なるサブネットで2つのインスタンスを起動し、単一のIPに対してVPCピアリングを許可する必要があります。
B. 複数のElastic IPアドレスを持つ複数のネットワークインターフェースを持つVPCインスタンスを作成します。
C. ACLとセキュリティグループの両方をアタッチし、IPアドレスごとに個別のルールを持つVPCインスタンスを作成します。
D. 複数のサブネットが接続され、それぞれに個別のIPアドレスが割り当てられるVPCインスタンスを作成します。
Answer: B
Explanation:
Virtual Private Cloud（VPC）は、ユーザーのAWSアカウント専用の仮想ネットワークです。ユーザーは、ユーザーが定義した仮想ネットワークにAWSリソースを起動できます。 VPCを使用すると、ユーザーは自分のインスタンスに複数のプライベートIPアドレスを指定できます。ユーザーがインスタンスに指定できるネットワークインターフェイスとプライベートIPアドレスの数は、インスタンスタイプによって異なります。各ネットワークインターフェイスで、組織はEIPを割り当てることができます。このシナリオは、ユーザーが単一のサーバーで複数のSSL証明書を使用し、各証明書を特定のEIPアドレスに関連付けることにより、単一のEC2インスタンスで複数のWebサイトをホストする場合に役立ちます。また、ファイアウォールや各ネットワークインターフェイスに複数のプライベートIPアドレスを持つロードバランサーなどのネットワークアプライアンスを運用するシナリオでも役立ちます。
http://docs.aws.amazon.com/AWSEC2/latest/UserGuide/MultipleIP.html

NEW QUESTION: 3
A developer wants to literate through an array of objects and count the objects whose property value, name, start with the letter N. const arrobj - [{''name ''t ''Zach''}, { ''name t Kate'') , ( ''name Alice'') < ( ''name'' t ''Bob'') , (''name'' t ''Nathan) , (''name'' t ''Nathandle1'')] Refer to the code snippet below:

Which missing lines 02 and 03 return the correct count?
A. Conset sun + curr. StartsWith ('N') 7 1 : 1;
Return acc + sum ;
B. Comst sum = curr. name startsWith ('N') 7 1 : 0;
Return curr + sum;
C. Const sum = curr. name startsWith ('N') 7 1 : 0;
Return curr + sum;
D. Comst sum = curr. Name startsWith ('N') 7 1 : 0
Return acc + sum;
Answer: D