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NEW QUESTION: 1
In a potential Access Manager for Web sale, the client is a large customer and has large numbers of applications and servers involved in their SSO/Web authorization plans. Oracle Access Manager (OAM) is the main competitor. What might you emphasize as you try to move the customer in your direction?
A. Access Manager both scales well and performs well.
B. Access Manager scales well and can do software distribution to any and all clients involved in the scope of the SSO engagement.
C. Access Manager is on a par with OAM from a scalability point of view, but it has a wider number of applications that it supports out of the box.
D. Access Manager for Web scales well, and is much easier to manage, given a relatively small number of Access Manager for Web servers involved, versus many OAM plug-ins to manage And the appliance version of Access Manager for Web provides faster time to value (TTV).
Answer: D

NEW QUESTION: 2

A. Option D
B. Option C
C. Option E
D. Option A
E. Option B
Answer: D,E
Explanation:
Spanning tree forces redundant data paths into a standby (blocked) state. If a network segment in the spanning tree fails and a redundant path exists, the spanning-tree algorithm recalculates the spanning-tree topology and activates the standby path. Switches send and receive spanning-tree frames, called bridge protocol data units (BPDUs), at regular intervals. The switches do not forward these frames but use them to construct a loop-free path. BPDUs contain informationabout the sending switch and its ports, including switch and MAC addresses, switch priority, port priority, and path cost. Spanning tree uses this information to elect the root switch and root port for the switched network and the root port and designated port for each switched segment. When two ports on a switch are part of a loop, the spanning-tree port priority and path cost settings control which port is put in the forwarding state and which is put in the blocking state. The spanning-tree port priority value represents the location of a port in the network topology and how well it is located to pass traffic. The path cost value represents the media speed.
Reference:http://www.cisco.com/c/en/us/td/docs/switches/lan/catalyst3750x_3560x/softwar e/release/12-2_55_se/configuration/guide/3750xscg/swstp.html

NEW QUESTION: 3





A. DECLARE @message NVARCHAR(1000),@severity INT, @state INT;
SELECT @message = ERROR_MESSAGE(), @severity = ERROR_SEVERITY(), @state
= ERROR_STATE();
THROW (@message, @severity, @state);
B. SELECT ERROR_LINE(), ERROR_MESSAGE()
C. DECLARE @message NVARCHAR(1000),@severity INT, @state INT;
SELECT @message = ERROR_MESSAGE(), @severity = ERROR_SEVERITY(), @state
= ERROR_STATE();
RAISERROR (@message, @severity, @state);
D. THROW;
Answer: C
Explanation:
Explanation
When the code in the CATCH block finishes, control passes to the statement immediately after the END CATCH statement. Errors trapped by a CATCH block are not returned to the calling application. If any part of the error information must be returned to the application, the code in the CATCH block must do so by using mechanisms such as SELECT result sets or the RAISERROR and PRINT statements.
Reference: TRY...CATCH (Transact-SQL)
https://msdn.microsoft.com/en-us/library/ms175976.aspx