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NEW QUESTION: 1

A. Option B
B. Option A
C. Option D
D. Option C
Answer: C

NEW QUESTION: 2
You have a Windows 8.1 Enterprise client computer named Computer1. The Storage Spaces settings of Computer1 are configured as shown in the following exhibit. (Click the Exhibit button.)

You plan to create a three-way mirror storage space in the storage pool and to set the size of the storage space to 50 GB You need to identify the minimum number of disks that must be added to the storage pool for the planned mirror.
How many disks should you identify?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
In Windows Server 2012 Storage Spaces and Windows 8Storage Spaces, a 2-way mirror requires at least
2 physical disks.
However, a 3-way mirror requires at least 5 physical disks.
The reason is that a 3-way mirror uses a quorum. In order to keep running, the mirror space must keep over 50% of the disks functioning.
So a 3-way mirror must have at least 5 physical disks to be able to survive the loss of up to 2physical disks.

NEW QUESTION: 3
A customer needs a 4-core S814 server with 1TB of available disk space to run an ERP application.
Which disk storage technology meets the requirements?
A. Internal hard disk
B. Flash
C. SAN
D. Internal Solid-State disk
Answer: A
Explanation:
Reference: http://www-03.ibm.com/systems/power/hardware/scale-out.html

NEW QUESTION: 4
You develop a Microsoft SQL Server 2012 database that contains tables named Employee and Person.
The tables have the following definitions:

Users are able to use single INSERT statements or INSERT...SELECT statements into this view.
You need to ensure that users are able to use a single statement to insert records into both Employee and Person tables by using the VwEmployee view.
Which Transact-SQL statement should you use?
A. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
INSTEAD OF INSERT
AS
BEGIN
DECLARE @ID INT, @FirstName NVARCHAR(25), @LastName NVARCHAR(25),
@PersonID
INT, @EmployeeNumber NVARCHAR(15)
SELECT @ID = ID, @FirstName = FirstName, @LastName = LastName,
@ EmployeeNumber = EmployeeNumber
FROM inserted
INSERT INTO Person(Id, FirstName, LastName)
VALUES(@ID, @FirstName, @LastName)
INSERT INTO Employee(PersonID, EmployeeNumber)
VALUES(@PersonID, @EmployeeNumber
END
B. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
INSTEAD OF INSERT
AS
BEGIN
INSERT INTO Person(Id, FirstName, LastName)
SELECT Id, FirstName, LastName FROM VwEmployee
INSERT INTO Employee(PersonID, EmployeeNumber)
SELECT Id, EmployeeNumber FROM VwEmployee
END
C. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
INSTEAD OF INSERT
AS
BEGIN
INSERT INTO Person(Id, FirstName, LastName)
SELECT Id, FirstName, LastName, FROM inserted
INSERT INTO Employee(PersonId, EmployeeNumber)
SELECT Id, EmployeeNumber FROM inserted
END
D. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
FOR INSERT
AS
BEGIN
INSERT INTO Person(Id, FirstName, LastName)
SELECT Id, FirstName, LastName, FROM inserted
INSERT INTO Employee(PersonId, EmployeeNumber)
SELECT Id, EmployeeNumber FROM inserted
END
Answer: C
Explanation:
Explanation/Reference:
Explanation: