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NEW QUESTION: 1

A. Option D
B. Option C
C. Option A
D. Option E
E. Option B
Answer: B,C,D
Explanation:
Reference:http://www.dianaromeo.info/virtualizacion/vmware/vsphere/update-manager

NEW QUESTION: 2
다음 중 프로젝트 팀 개발 프로세스에 대한 의견은 무엇입니까?
A. 조직 프로세스 자산
B. 프로젝트 담당자 지정
C. 실적 보고서
D. 기업 환경 요인
Answer: B

NEW QUESTION: 3
What type of class definition can be used to define multiple inheritance?
A. Class
B. Abstract
C. Interface
D. Final
Answer: C

NEW QUESTION: 4
Push the Exhibit Button to load the referenced "XML Document". Create an XML Schema Document for "XML Document". The definitions of this XML Schema Document require that the value of the level attribute of the record element must be singularly unique within the XML document, and further, that the level attribute of the scenario element must reference the value of the level attribute of the record element. Select which of the following correctly describes what should be written in " XML Schema " document (1).

A. <xs:element name="TestML" type="testmlType">
< xs:unique name= " LEVEL " >
<xs:selector xpath= " record " />
<xs:field xpath= " record/@level " />
</ xs:unique >
< xs:ref name= " levelRef " refer= " LEVEL " >
<xs:selector xpath= " scenario " />
<xs:field xpath= " scenario/@level " />
</ xs:ref >
</xs:element>
B. <xs:element name="TestML" type="testmlType">
< xs:key name= " LEVEL " >
<xs:selector xpath= " record " />
<xs:field xpath= " @level " />
</ xs:key >
< xs:keyref name= " levelRef " refer= " LEVEL " >
<xs:selector xpath= " scenario " />
<xs:field xpath= " @level " />
</ xs:keyref >
</xs:element>
C. <xs:element name="TestML" type="testmlType">
< xs:unique name= " LEVEL " >
<xs:selector xpath= " record " />
<xs:field xpath= " @level " />
</ xs:unique >
< xs:ref name= " levelRef " refer= " LEVEL " >
<xs:selector xpath= " scenario " />
<xs:field xpath= " @level " />
</ xs:ref >
</xs:element>
D. <xs:element name="TestML" type="testmlType">
< xs:key name= " LEVEL " >
<xs:selector xpath= " record " />
<xs:field xpath= " record/@level " />
</ xs:key >
< xs:keyref name= " levelRef " refer= " LEVEL " >
<xs:selector xpath= " scenario " />
<xs:field xpath= " scenario/@level " />
</ xs:keyref >
</xs:element>
Answer: B