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NEW QUESTION: 1
Assuming there are open connections through an active system's NAT and a failover occurs, by default, what happens to those connections?

A. All open connections are lost, but new connections are initiated by the newly active BIG-IP, resulting in minimal client downtime.
B. The "Mirror" option must be chosen on the NAT and the setting synchronized prior to the connection establishment.
C. All open connections will be maintained.
D. All open connections will be lost.
E. Long-lived connections such as Telnet and FTP will be maintained while short-lived connections such as HTTP will be lost.
Answer: C

NEW QUESTION: 2
You have defined the transportation zone hierarchy shown in the attached screenshot. Which transportation lanes can you use for a transport that originates in transportation zone 4 and ends in transportation zone 5?
There are 3 correct answers to this question.

A. 5->4
B. 4->1
C. 2->3
D. 2->1
E. 1->5
Answer: A,D,E

NEW QUESTION: 3
展示を参照してください。

このコマンドは、CiscoルータのSNMPサーバを設定するために使用されます。 SNMPサーバ用の暗号化パスワードはどのオプションですか？
A. snmp
B. group-1
C. sha
D. snmpv3
Answer: D

NEW QUESTION: 4
Examine the structure of the EMPLOYEES table:

There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the name, joining date, and manager for all employees. Newly hired employees are yet to be assigned a department or a manager. For them, 'No Manager' should be displayed in the MANAGER column.
Which SQL query gets the required output?
A. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e RIGHT OUTER JOIN employees mON (e.manager_id = m.employee_id);
B. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
C. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e NATURAL JOIN employees mON (e.manager_id = m.employee_id).
D. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e JOIN employees mON (e.manager_id = m.employee_id);
Answer: B