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NEW QUESTION: 1
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.1.0.0.0.0
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.0.255.255.255.254
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 2
You develop a Windows Presentation Foundation (WPF) application. This application is used to output data trends to customer service representatives.
You use threading to keep the UI responsive. You have a function named UpdateUI that updates all of the UI components.
You use the following code to update the _Data variable. (Line numbers included for reference only.)

You need to update the user interface without knowing if you are on the UI thread.
Which code segment should you insert at line 06?
A. Me. Dispatcher.VerifyAccess ()
UpdateUI()
B. Me.Dispatcher.VerifyAccess()
Dim [function] = New Action(AddressCf UpdateUI)
Dim args() As Object = Nothing
Me .Dispatcher .BeginlnvoJce ([function], args)
C. If (Me.Dispatcher.CheckAcce33()) Then
Dim [function] = New Action(Addre33Cf UpdateUI)
Dim args() As Object = Nothing
Me.Dispatcher.Beginlnvoke([function], args)
Else
UpdateUI()
End If
D. If (Me. Dispatcher. CheckAccess())
Then UpdateUI()
Else
Dim (function] = New Action(AddressCf OpdateUI)
Dim args() As Object = Nothing
Me .Dispatcher ,BeginInvoIce ( [function; , args)
End If
Answer: D

NEW QUESTION: 3
What is the highest numbered TCP/IP port?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
There are 65535 possible ports officially recognized. Note: TCP uses the notion of port numbers to identify sending and receiving applications. Each side of a TCP connection has an associated 16-bit unsigned port number assigned to the sending or receiving application. Ports are categorized into three basic categories: well known, registered and dynamic/private. The well known ports are assigned by the Internet Assigned Numbers uthority (IANA) and are typically used by system-level or root processes. Well known applications running as servers and passively listening for connections typically use these ports. Some examples include: FTP (21), TELNET (23), SMTP (25) and HTTP (80). Registered ports are typically used by end user applications as ephemeral source ports when contacting servers, but they can also identify named services that have been registered by a third party. Dynamic/private ports can also be used by end user applications, but are less commonly so. Dynamic/private ports do not contain any meaning outside of any particular TCP connection. com

NEW QUESTION: 4
Your case management solution requires case workers to have a view of information managed in a system external to IBM Case Manager and P8. How do you integrate such a view into the IBM Case Manager case worker's environment?
A. Extend the Case Information Widget
B. Use an IBM Forms Widget
C. Use the Case Data Widget
D. Integrate a mashup widget that displays the external system information
Answer: D