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NEW QUESTION: 1
You are modifying a Windows Communication Foundation (WCF) service that issues security tokens. The service is accessible through the named pipe protocol. No endpoints are added in the service code. The configuration file for the service is as follows. (Line numbers are included for reference only.)

You need to ensure that new and existing client applications can access the service through HTTP and named pipes.
What should you do?
A. Insert the following line at line 05. <endpoint address="http://www.contoso.com" binding="basicHttpBinding" contract="Contoso.TokenService" />
B. Insert the following line at line 08. <add baseAddress="http://www.contoso.com" />
C. Insert the following line at line 05. <endpoint address=http://www.contoso.com binding="wsHttpBinding" contract="Contoso.TokenService" />
D. Insert the following line at line 08. < add baseAddress="net.tcp://www.contoso.com:8090" />
Answer: B

NEW QUESTION: 2
In an organization, the workflow as shown in the screen shot, is to be triggered when an employee is transferred from one department to another.
What happens during this workflow process?
There are 2 correct answers to this question.

A. The employee's future manager will get a notification immediately after this workflow is triggered
B. The employee's current manage can send back the workflow to the employee's future manager for some
'-' changes in the data
C. Anyone in the Recruiting team can send back the workflow to the employee's future manager for some
'-' changes in the data
D. The Head of the Business Unit of the employee's new department will get a notification immediately after 1-' this workflow is triggered
Answer: A,D

NEW QUESTION: 3
Your network contains a System Center 2012 Configuration Manager environment.
You need to create a report that lists all of the client computers that do not have an Application named App1 installed.
Which query should you use to create the report?
A. SELECT SYS.Netbios_Name0, ARP.DisplayName0 FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP. ResourceID WHERE ARP.DisplayName0 NOT IN ('App1')
B. SELECT SYS.Netbios_Name0 from v_R_System SYS WHERE SYS.ResourceID NOT IN (SELECT SYS.ResourceID FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID WHERE ARP.DisplayName0 = 'App1')
C. SELECT SYS.Netbios_Name0 from v_R_System SYS WHERE SYS.ResourceID IN (SELECT SYS.ResourceID FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID. WHERE ARP.DisplayName0 = 'App1')
D. SELECT SYS.Netbios_Name0, ARP.DisplayName0 FROM v_R_System AS SYS INNER JOIN V_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID WHERE ARP.DisplayName0 NOT LIKE 'App1'
Answer: B
Explanation:
SELECT computer name FROM table v_R_System (SQL Syntax)
WHERE resource ResourceID is NOT IN
Add Remove Programs WHERE DisplayName0 = 'App1'
SQL INNER JOIN Keyword
The INNER JOIN keyword returns rows when there is at least one match in both tables.
Reference: http://www.w3schools.com/sql/sql_join_inner.asp