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NEW QUESTION: 1
ある企業が、複数のAmazon S3バケットから暗号化されていない多数の小さなファイルを一元管理しています。会社は、集中化後にファイルに同じデータが含まれていることを確認する必要があります。
どの方法が要件を満たしていますか？
A. SIG v4と比較して、送信元オブジェクトと宛先オブジェクトに対してHEAD要求を発行します。
B. 移動元と移動先のオブジェクトのサイズを比較します。
C. ソースオブジェクトと宛先オブジェクトに対してS3 CompareObjects APIを呼び出します。
D. 転送元オブジェクトと転送先オブジェクトのS3タグを比較します。
Answer: D

NEW QUESTION: 2
You have two SQL Server 2014 instances named SQLDev and SQLProd.
You plan to create a new database on SQLProd that will use SQL Server Authentication.
You need to ensure that when the new database is copied from SQLProd to SQLDev, users can connect to the database on SQLDev even if they do not have a login on the SQLDev instance.
What should you use?
More than one answer choice may achieve the goal. Select the BEST answer.
A. SQL Server Analysis Services (SSAS) scripts
B. Triggers
C. SQL Server Integration Services (SSIS) scripts
D. Contained database
E. Extended Events
Answer: D
Explanation:
A fully contained database includes all the settings and metadata required to define the database and has no configuration dependencies on the instance of the SQL Server Database Engine where the database is installed.
Reference: Contained Databases

NEW QUESTION: 3
複数のIPv6アドレスが単一のインターフェイスに設定されている場合、OSPFv3はどのアドレスプレフィックスを使用しますか？
A. インターフェース上のすべてのプレフィックス
B. インターフェイスの最高のプレフィックス
C. インターフェースの最も低いプレフィックス
D. 管理者がOSPFv3の使用のために構成するプレフィックス
Answer: A

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
H. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx