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NEW QUESTION: 1
Click the Exhibit button.

Referring to the exhibit,
what information is provided about the route to 192.168.47.0/24?
(Choose two.)
A. There is a single active route to 192.168.47.0/24.
B. There is a single next hop available to 192.168.47.0/24.
C. There are two next hops available to 192.168.47.0/24.
D. There are two active routes to 192.168.47.0/24.
Answer: A,C

NEW QUESTION: 2
James works as a Database Designer for Tech Perfect Inc. The company has a Windows Vista-based computer with Microsoft Office 2010 installed on it. The computer has a database named Accounts and two tables named Table1 and Table2, which are created in Microsoft Office Access 2010. James wants to apply referential integrity to establish a relationship between these tables. Which of the following are required to accomplish the task?
Each correct answer represents a part of the solution. Choose three.
A. The related fields contain the same format.
B. Table1 and Table2 are related to the same database.
C. The related field must have different formats.
D. The common field is the primary key of the primary table.
Answer: A,B,D
Explanation:
The following are required for establishing referential integrity between two tables:
The common field is the primary key of the primary table.
The related fields contain the same format.
Both tables are related to the same database.
Answer D is incorrect. In order to establish referential integrity, it is required that both tables have the same format.

NEW QUESTION: 3
You use Microsoft .NET Framework 4 to create a Windows Forms application.
The application has a reference to a Windows Presentation Foundation (WPF) class library
named Library1. Library1 contains a WPF user control named UserControl1.
You add the following code to the application:

You need to ensure that you can add the instance of UserControl1 to a control named host in Form1.
Which code segment should you insert at line 09?
A. WindowsFormsHost host = new WindowsFormsHost ();
B. ElementHost host = new ElementHost();
C. Panel host = new Panel();
D. ContainerControl host = new ContainerControl();
Answer: B

NEW QUESTION: 4
展示を参照してください。

R1はVRF-Liteで設定され、R2をpingできます。 R2は完全に設定されていますが、vrf YellowにはアクティブなEIGRPネイバーがありません。 R2の設定が完了している場合、vrf YellowのEIGRP 100ネイバー関係が形成されないのはどの問題ですか？
A. EIGRPネイバー関係の形成を妨げるレイヤー1の問題があります
B. インターフェースIPアドレスが同じサブネットにありません
C. EIGRP 100ネットワーク192 168 1 0/24はR1のグローバルルーティングテーブルで設定されます
D. no auto-summaryコマンドは、EIGRPネイバー関係の形成を妨げています
Answer: C