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NEW QUESTION: 1
A user notices the department laser printer is printing light. Which of the following items should a technician do FIRST to fix this issue?
A. Perform a full power cycle on the printer.
B. Clean the paper path with a damp cloth and canned air to remove any debris.
C. Install a maintenance kit and reset all page counts to zero.
D. Remove and clean the fuser assembly with an alcohol based cleaner.
Answer: C

NEW QUESTION: 2
You are setting up an owner Access Profile and you want to set the access level for the Opportunity related information section on the Account Detail page. One of the access level options is Inherit Primary.
What determines the access level for related Opportunity records if you select this option?
A. The default Account Detail page layout for the company.
B. The access level set for the Account object.
C. The access level set for the Opportunity related information section in the default Access Profile.
D. The access level set for the Opportunity object.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The Inherit Primary access level is available for certain one-to-many and many-to-many related record types only. With the Inherit Primary access level, the behavior of the related records is as follows:
* Only the related child records that the user is authorized to see are shown in the list of related records.
* Each related record inherits the access level from its own primary record type rather than the access level of the parent record type in the relationship.

NEW QUESTION: 3
You are configuring on alarm In Oracle Cloud Infrastructure (OCI) for a compute instance named vision. The metric needs to be triggered when the ingress network rate is greater than 1MB.
Which statement will accomplish this?
A. {resourceDisplayName = "vision"}(NetworksBytesIn[lm]).rate() > 1024
B. {resourceDisplayName = Hvision"}(NetworksBytesIn[1MB]).rate() > 1
C. NetworksBytesIn[1m]{resourceDisplayName - "vision"}.rate() > 1024
D. NetworksBytesIn[1MB]{resourceDisplayName - "vision"}.rate() > 1
Answer: C
Explanation:
NetworkBytesIn is aggregated across all the instance's attached VNICs
Example
The query components appear in the following order:
metric[interval]{dimensionname="dimensionvalue"}.groupingfunction.statistic
https://docs.cloud.oracle.com/en-us/iaas/Content/Monitoring/Reference/mql.htm

NEW QUESTION: 4
Communication is the key to the success of a project. As the project manager, you have four stakeholders with whom you need to communicate. As such, you have six channels of communication. A new stakeholder has been added that you also need to communicate with. How many communication channels do you have now?
A. 0
B. 1
C. 2
D. 3
Answer: B
Explanation:
5*4/2 = 10, If you are the PM and have four stakeholders to communicate with, there are 5 people involved and 10 channels. When you add a new stakeholder, you have 6 people and 15 channels. The formula stated in this question is N(N-1)/2 where N equals the number of people. How to derive this Formula: The Attached calculation will help to realize the concept of communication channel. Say, there are "n" Persons and they are having communication with each other. We need to find how many communication channels are possible here. Take the case of the first person. He can communicate with rest of the (n-1) person. So, here are (n-1) communication channels. The Second person can communicate with ((n-1)-1) person because his communication with the first person is already taken into account for the calculation of first person. So, here are (n-2) communication channels. Similarly, the third person can communicate with ((n-1)-2) because his communication with the first and second person is already taken into account for the calculation of first and second person. So, it's (n-3) channels.Like that, if we proceed, the total no of Channels used by n person, will be = (n-1)+(n-2)+(n-3)+......+1 = 1+2+3+.....+(n-1)We have a sum of an AP series for "(n-1)" number whose first number is "1" and the common difference is also "1".The Formula for Sum of AP series is: S = n[2a+(n-1)d]/2(where, n = total numbers, a = first number, d = common difference) So, it gives us the Total Communication Channel=(n-1) *[2*1+((n-1)-1)*1]/2 = (n1)*[2+(n-2)]/2 = n*(n-1)/2 Hope this helps.