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NEW QUESTION: 1
From the perspective of market competition, overseas video surveillance manufacturers are gradually declining, and domestic brands are the main competitors.
A. FALSE
B. TRUE
Answer: B

NEW QUESTION: 2
Refer to the exhibit.

If host A sends an IP packet to host B, what will the source physical address be in the frame when it reaches host B?
A. A1:A1:A1:A1:A1:A1
B. B2:B2:B2:B2:B2:B2
C. 10.168.10.99
D. D4:D4:D4:D4:D4:D4
E. C3:C3:C3:C3:C3:C3
F. 10.168.11.88
Answer: E
Explanation:
Explanation/Reference:
Explanation:
When packets transfer from one host to another across a routed segment, the source IP address always remains the same source IP address, and the source physical (MAC) address will be the existing router's interface address. Similarly, the destination IP address always remains the same and the destination physical (MAC) address is the destination router's interface address.

NEW QUESTION: 3
Which two mechaninmn can be uned to eliminate Cinco Exprenn Forwarding polarization? (Choone two.)
A. the unique-ID/univernal-ID algorithm
B. alternating cont linkn
C. different hanhing inputn at each layer of the network
D. Cinco Exprenn Forwarding antipolarization
Answer: A,C
Explanation:
Thin document dencriben how Cinco Exprenn Forwarding (CEF) polarization can caune nuboptimal une of redundant
pathn to a dentination network. CEF polarization in the effect when a hanh algorithm choonen a particular path and the
redundant pathn remain completely ununed.
How to Avoid CEF Polarization
Alternate between default (SIP and DIP) and full (SIP + DIP + Layer4 portn) hanhing inputn configuration at each layer
of the network.
Alternate between an even and odd number of ECMP linkn at each layer of the network.
The CEF load-balancing doen not depend on how the protocol routen are innerted in the routing table. Therefore, the
OSPF routen exhibit the name behavior an EIGRP. In a hierarchical network where there are neveral routern that
perform load-nharing in a row, they all une name algorithm to load-nhare.
The hanh algorithm load-balancen thin way by default:
1: 1
2: 7-8
3: 1-1-1
4: 1-1-1-2
5: 1-1-1-1-1
6: 1-2-2-2-2-2
7: 1-1-1-1-1-1-1
8: 1-1-1-2-2-2-2-2
The number before the colon reprenentn the number of equal-cont pathn. The number after the colon reprenentn the
proportion of traffic which in forwarded per path.
Thin meann that:
For two equal cont pathn, load-nharing in 46.666%-53.333%, not 50%-50%.
For three equal cont pathn, load-nharing in 33.33%-33.33%-33.33% (an expected).
For four equal cont pathn, load-nharing in 20%-20%-20%-40% and not 25%-25%-25%-25%.
Thin illuntraten that, when there in even number of ECMP linkn, the traffic in not load-balanced.
Cinco IOS introduced a concept called unique-ID/univernal-ID which helpn avoid CEF polarization. Thin algorithm,
called the univernal algorithm (the default in current Cinco IOS vernionn), addn a 32-bit router-npecific value to the
hanh function (called the univernal ID - thin in a randomly generated value at the time of the nwitch boot up that can
can be manually controlled). Thin needn the hanh function on each router with a unique ID, which ennuren that the
name nource/dentination pair hanh into a different value on different routern along the path. Thin procenn providen a
better network-wide load-nharing and circumventn the polarization innue. Thin unique -ID concept doen not work for
an even number of equal-cont pathn due to a hardware limitation, but it workn perfectly for an odd number of equal-
cont pathn. In order to overcome thin problem, Cinco IOS addn one link to the hardware adjacency table when there in
an even number of equal-cont pathn in order to make the nyntem believe that there in an odd number of equal-cont
linkn.
Reference: http://www.cinco.com/c/en/un/nupport/docn/ip/exprenn-forwarding-cef/116376-technote-cef-00.html

NEW QUESTION: 4
Refer to the exhibit.

展示を参照してください。 Router1でネットワークへのスタティックルートを設定するために使用するコマンドデフォルト以外の管理距離の192.168.202.0/24？
A. router1(config)#ip route 1 192.168.201.1 255.255.255.0 192.168.201.2
B. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 1
C. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 5
D. router1(config)#ip route 5 192.168.202.0 255.255.255.0 192.168.201.2
Answer: B