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NEW QUESTION: 1

A. Option D
B. Option C
C. Option A
D. Option B
Answer: A,B

NEW QUESTION: 2
Which of the following BEST describes the weakness in WEP encryption?
A. The WEP key is stored in plain text and split in portions across 224 packets of random data. Once enough packets are sniffed the IV portion of the packets can be removed leaving the plain text key.
B. The initialization vector of WEP uses a crack-able RC4 encryption algorithm. Once enough packets are captured an XOR operation can be performed and the asymmetric keys can be derived.
C. The WEP key has a weak MD4 hashing algorithm used. A simple rainbow table can be used to generate key possibilities due to MD4 collisions.
D. The WEP key is stored with a very small pool of random numbers to make the cipher text. As the random numbers are often reused it becomes easy to derive the remaining WEP key.
Answer: D

NEW QUESTION: 3
The SAS data set ONE contains fifty million observations and contains the variable PRICE, QUANTITY, FIXED and VARIABLE. Which SAS program successfully creates three new variables TOTREV, TOTCOST and PROFIT and requires the least amount of CPU resources to be processed?
A. data two;
Set one;
Where totrev>1000;
Totrev=sum(price*quantity);
Totcost=sum(fixed,variable);
Profit=sum(totrev,-totcost);
Run;
B. data two;
Set one;
totrev=sum(price*quantity);
where totrev>1000;
totcost=sum(fixed,variable);
profit=sum(totrev,-totcost);
run;
C. data two;
Set one;
Totrev = sum(price*quantity);
Totcost= sum(fixed,variable);
If totrev>1000;
Profit=sum(totrev,-totcost);
Run;
D. data two;
Set one;
Totrev=sum(price*quantity);
If totrev>1000;
Totcost=sum(fixed,variable);
Profit=sum(totrev,-totcost);
Run;
Answer: D

NEW QUESTION: 4
you are editing a form. What form attribute must
be unique?
Note: There are 1 correct answers to this question.
A. Print Count
B. Client Code
C. Reason
D. Order
Answer: D