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NEW QUESTION: 1
CORRECT TEXT
Problem Scenario 58 : You have been given below code snippet.
val a = sc.parallelize(List("dog", "tiger", "lion", "cat", "spider", "eagle"), 2) val b = a.keyBy(_.length) operation1
Write a correct code snippet for operationl which will produce desired output, shown below.
Array[(lnt, Seq[String])] = Array((4,ArrayBuffer(lion)), (6,ArrayBuffer(spider)),
(3,ArrayBuffer(dog, cat)), (5,ArrayBuffer(tiger, eagle}}}
Answer:
Explanation:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
b.groupByKey.collect
groupByKey [Pair]
Very similar to groupBy, but instead of supplying a function, the key-component of each pair will automatically be presented to the partitioner.
Listing Variants
def groupByKeyQ: RDD[(K, lterable[V]}]
def groupByKey(numPartittons: Int): RDD[(K, lterable[V] )]
def groupByKey(partitioner: Partitioner): RDD[(K, lterable[V])]

NEW QUESTION: 2
Which statement about OSPF loop prevention is true?
A. The ASBR uses type 3 LSAs from non-backbone areas to prevent control-plane routing loops.
B. The ABR can filter type 3 LSPs to prevent routing loops.
C. The DN bit ignores LSA types 2, 3, and 5 to prevent routing loops.
D. The discard route is generated automatically on the ABR to prevent routing loops.
Answer: D

NEW QUESTION: 3
Given the SAS data set SAUSER.HIGWAY:
SASUSER.HIGHWAY

The following SAS program is submitted:
% macro highway;
proc sql nonprint;
% let numgrp=6;
select distinct status into:group1-:group&numgrp from sasuser.highway;
quit;
% do i=1 %to &numgrp;
proc print data =sasuser.highway;
where status ="&&group&I";
run;
% end;
% mend;
% highway
How many reports are produced?
A. 0
B. 1
C. 2
D. 3
Answer: C